Question

resuelve los siguientes ejercicios.

AYUDA POR FAVOR!!!!​

Answer 1

[tex] {( \sqrt{x - 8}) }^{2} = {2}^{2} [/tex]

[tex]x - 8 = 4[/tex]

[tex]x = 4 + 8[/tex]

[tex]x = 12[/tex]

[tex]5 = \sqrt{3x + 1} [/tex]

[tex] {5}^{2} = {( \sqrt{3x - 1} )}^{2} [/tex]

[tex]25 = 3x + 1[/tex]

[tex]3x = 25 - 1[/tex]

[tex]3x = 24[/tex]

X=24/3

X=8

[tex] \sqrt{5x - 4} = 4[/tex]

[tex] {( \sqrt{5x - 4}) }^{2} = {4}^{2} [/tex]

[tex]5x - 4 = 16[/tex]

[tex]5x = 4 + 16[/tex]

[tex]5x = 20[/tex]

[tex]x = \frac{20}{5} [/tex]

[tex]x = 4[/tex]

[tex] ({ \sqrt{x + 3} )}^{2} = {( \sqrt{5x + 1} )}^{2} [/tex]

[tex]5x + 1 = x + 3[/tex]

[tex]5x - x = 3 - 1[/tex]

[tex]4x = 2[/tex]

[tex]x = \frac{1}{2} [/tex]

[tex] \sqrt{x + 2} = \sqrt{ \frac{4x + 8}{4} } [/tex]

[tex] {( \sqrt{x + 2)} }^{2} = {( \sqrt{ \frac{4x + 8}{4} } }^{2} [/tex]

[tex]x + 2 = \frac{4x + 8}{4} [/tex]

[tex]4(x + 2) = 4x + 8[/tex]

[tex]4x + 8 = 4x + 8[/tex]

aca nos percatamos que son iguales en ambos miembros,es una identidad