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5x-4y=4 (3)
solución/ -8x+12y=-12
15x-12y=12
7x=0
x=0÷7=0
2(0)-3y=3
0-3y=3
y=3÷-3=-1
+2(5x-4y=4)
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-10x+15y=-15
+10x-8y=8
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7y=-7
y=-1
Reemplazando
2x-3y=3
2x-3(-1)=3
2x=0
x=0
Espero haberte ayudado ;3