Question

resuelve las siguientes ecuaciones
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Answer 1

[tex]15x-10=6x-(x+2)+(-x+3)\\15x-10=6x-\left(x+2\right)-x+3\\15x-10=6x-x-\left(x+2\right)+3\\15x-10+10=4x+1+10\\15x=4x+11\\15x-4x=4x+11-4x\\11x=11\\\frac{11x}{11}=\frac{11}{11}\\x=1[/tex]

[tex](5-3x)-(-4+6)=(8x+11)-(3x-6)\\5-3x-\left(-4+6\right)=\left(8x+11\right)-\left(3x-6\right)\\-3x+5-2=\left(8x+11\right)-\left(3x-6\right)\\-3x+3=8x+11-\left(3x-6\right)\\-3x+3=5x+17\\-3x+3-3=5x+17-3\\-3x=5x+14\\-3x-5x=5x+14-5x\\-8x=14\\\frac{-8x}{-8}=\frac{14}{-8}\\x=-\frac{7}{4}[/tex]

[tex]15x+(-6x+5)-2-(-x+3)=-(7x+23)-x+(3-2x)\\15x-6x+5-2-\left(-x+3\right)=-\left(7x+23\right)-x+\left(3-2x\right)\\9x+5-2-\left(-x+3\right)=-\left(7x+23\right)-x+\left(3-2x\right)\\9x+5-2-\left(-x+3\right)=-\left(7x+23\right)-x+3-2x\\9x+5-2-\left(-x+3\right)=-x-2x-\left(7x+23\right)+3\\9x+5-2-\left(-x+3\right)=-3x-\left(7x+23\right)+3\\10x=-10x-20\\10x+10x=-10x-20+10x\\20x=-20\\\frac{20x}{20}=\frac{-20}{20}\\x=-1[/tex]

Answer 2

Respuesta:

xd  29ue90384

Explicación paso a paso:

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