Resuelve este sistema con dos incognitas
3x + 2y = 3
-x + y = -1
3x + 2y = 3
-x + y = -1
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-x + y = -1 .......(2)
En (2):
y + 1 = x
En (1):
3x + 2y = 3
3( y + 1 ) + 2y = 3
3y + 3 + 2y = 3
5y = 3 - 3
5y = 0
y = 0
En (1):
-x + y = -1
-x + 0 = -1
1 + 0 = x
x = 1
Rpta: x = 1 ; y = 0