Question

Resuelvannn... 16x−[3x−(6-9x)]=30x+[(-3x+2)−(x+3)]

Answer 1

16x−[3x−(6-9x)]=30x+[(-3x+2)−(x+3)]

16x−[3x−6+9x]=30x+[-3x+2−x-3]

16x−[12x−6]=30x+[-4x-1]

16x−12x+6 = 30x-4x-1

4x + 6 =  26x - 1

6+1 = 26x -4x

7 = 22x

7/22 = x