Question

Resuelva los ejercicios dados a continuacion, aplicando las leyes de las potencias.
porfa ayuda ​

Answer 1

Verified answer

[tex] {4}^{3} \times {4}^{ - 2} \times {4}^{2} = {4}^{3 - 2 + 2} = {4}^{3} = 64[/tex]

[tex]( {5}^{3} {)}^{2} = {5}^{3 \times 2} = {5}^{6} [/tex]

[tex] {6}^{ - 2} = \frac{1}{ {6}^{2} } = \frac{1}{36} [/tex]

[tex] {49}^{ \frac{1}{2} } = \sqrt{49} = 7[/tex]

[tex]( \frac{5}{3} {)}^{ - 3} = ( \frac{3}{5} {)}^{3} = \frac{27}{125} [/tex]

[tex] \frac{ {5}^{4} }{ {5}^{2} } = {5}^{4 - 2} = {5}^{2} = 25[/tex]

[tex] \frac{ {m}^{3} }{ {m}^{7} } = {m}^{3 - 7} = {m}^{ - 4} = \frac{1}{ {m}^{4} } [/tex]