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Metodo de reducción.
3x + 4y = 10 (1)
x - 4y = -2 (2) Sumamos (1) Y (2)
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4x = 8
x = 8/4
x = 2 Resmplazas este valor en (2)
x - 4y = - 2
x + 2 = 4y
2 + 2 = 4y
4 = 4y
4/4 = y
1 = y
Solución.
(2, 1)