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log(6X - 1) - log(X + 4) = logX
por propiedades: log(6X - 1) - log(X + 4) = log[(6X - 1)/(X + 4)]
log[(6X - 1)/(X + 4)] = logX
aplicamos lo siguiente:
(6X - 1) = X(X + 4)
6X - 1 = X² + 4X
X² + 4X - 6X + 1 = 0
X² - 2X + 1 = 0
Donde: a = 1; b = -2; c = 1
X = 2/2
X = 1
Rta: X = 1
Probemos
log[6(1) - 1] - log[1 + 4] = log(1)
log(5) - log(5) = log(1)
0 = 0
RTA: X = 1