Question

. Resolver las siguientes ecuaciones:
a) 3(2x− 5) + 5(3x− 1) = 7(x− 3) + 15
b) 7x+ 3(5x− 3) − (5x+ 1) = 7(2x+ 2)
c) 5x− 4(3x− 1) − (6x+ 1) = 5(3x+ 12) − 1

Answer 1

A)

3(2x− 5) + 5(3x− 1) = 7(x− 3) + 15

6x - 15 + 15x - 5 = 7x - 21 + 15

-20 + 6 = 7x - 21x

-14 = -14x

14x = 14

x = 14/14

x = 1

b)

7x+ 3(5x− 3) − (5x+ 1) = 7(2x+ 2)

7x + 15x - 9 - 5x - 1 = 14x + 14

17x - 14x = 14 + 10

3x = 24

x = 24/3

x = 8

c)


5x− 4(3x− 1) − (6x+ 1) = 5(3x+ 12) − 1

5x - 12x + 4 - 6x - 1 = 15x + 60 - 1

-13x - 15x = 59 - 3

-56 = 28x

-56/28 = x

-2 = x


Espero te sirva ;)