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x = [-b±√(b² -4ac)]/(2a)
x = [-(-1)±√((-1)² -4*1*52)]/(2*1)
x = [1±√(1-208)]/2
x = [1±√(-207)]/2
x = [1±14.388 i]/2
x1 = [1+14.388 i]/2 x2 = [1-14.388 i]/2
x1 = 0.5 + 7.194 i x2 = 0.5 - 7.194 i
2)x²-12x-120=0
x = [-b±√(b² -4ac)]/(2a)
x = [-(-12)±√((-12)² -4*1*(-120))]/(2*1)
x = [12±√(144+480)]/2
x = [12±√(624)]/2
x = [12±24.98]/2
x1 = [12+24.98]/2 x2 = [12-24.98]/2
x1 = [36.98]/2 x2 = -12.98/2
x1 = 18.49 x2 = -6.49
3)x²+4x=0
x(x+4)
x=0 x+4 =0
x1= 0 x2 = -4