Question

Resolver con proceso

Answer 1

Respuesta:

[tex]a) \frac{ {( \frac{1}{8} )}^{4} \times {( \frac{1}{8} )}^{9} }{ {( \frac{1}{8} )}^{7} } = \frac{ {( \frac{1}{8} )}^{4 + 9} }{ {( \frac{1}{8} )}^{7} } = \frac{ {( \frac{1}{8} )}^{13} }{ {( \frac{1}{8} )}^{7} } = {( \frac{1}{8} )}^{13 - 7} = {( \frac{1}{8} )}^{6} [/tex]

[tex]b) [ {( \frac{1}{3} )}^{ - 6} ] ^{2} = {( \frac{1}{3} )}^{ - 6 \times 2} = {( \frac{1}{3} )}^{ - 12} = {3}^{12} [/tex]

[tex]c) \frac{ {( \frac{3}{4} )}^{4} }{ {( \frac{3}{4} )}^{2} } = {( \frac{3}{4} )}^{4 - 2} = {( \frac{3}{4} )}^{2} = \frac{9}{16} [/tex]

[tex]d) {( \frac{2}{9} )}^{ - 3} \div {( \frac{2}{9} )}^{5} = {( \frac{2}{9} )}^{ - 3 - 5 } = {( \frac{2}{9} )}^{ - 8} = {( \frac{9}{2} )}^{8} [/tex]

[tex]e) [ {( \frac{1}{3} )}^{2} ] ^{3} \times {( \frac{1}{3} )}^{2} = {( \frac{1}{3} )}^{2 \times 3} \times {( \frac{1}{3} )}^{2} = {( \frac{1}{3} )}^{6} \times {( \frac{1}{3} )}^{2} = {( \frac{1}{3} )}^{6 + 2} = {( \frac{1}{3} )}^{8} [/tex]

[tex]f)( - \frac{3}{9} ) \times {( - \frac{3}{9} )}^{ - 1} = {( - \frac{3}{9} )}^{1 + ( - 1)} = {( - \frac{3}{9} )}^{0} = 1[/tex]