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sacamos trecia:
3 ( x² - x - 20 ) = 0
x² - x - 20 = 0
(x - ) (x + ) = 0
Buscamos dos numeros que sumados den -1 y que multiplicados den -20:
Los numeros son: 5 y -4
entonces:
3x² - 3x - 60 = 0
x² - x - 20 = 0
(x - 4 ) (x + 5 ) = 0
donde: x - 4 = 0 y x + 5 = 0
x = 4 y x= -5