Respuesta:
a. 0.644 atm.
b. ºC = 29.85
c. 1.2383 atm
d. K = 256.15
e. V = 0.548 L
Explicación:
Realiza las siguientes conversiones en
las unidades adecuadas.
a. De 490 mmHg → atm
1 atm --- 760 mmHg
x --- 490 mmHg
x = 0.644 atm
b. 303 K → °C
ºC = K - 273.15
ºC = 303 - 273.15
ºC = 29.85
c. 125 478 Pa → ? atm
1 Pa ---- 9.869 x 10⁻⁶ atm
125478 Pa ----- x
x = 1.2383 atm
d. -17°C → K
K = ºC + 273.15
K = -17 + 273.15
K = 256.15
e. 548 mL → L
V = 548 / 1000
V = 0.548 L
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Verified answer
Respuesta:
a. 0.644 atm.
b. ºC = 29.85
c. 1.2383 atm
d. K = 256.15
e. V = 0.548 L
Explicación:
Realiza las siguientes conversiones en
las unidades adecuadas.
a. De 490 mmHg → atm
1 atm --- 760 mmHg
x --- 490 mmHg
x = 0.644 atm
b. 303 K → °C
ºC = K - 273.15
ºC = 303 - 273.15
ºC = 29.85
c. 125 478 Pa → ? atm
1 Pa ---- 9.869 x 10⁻⁶ atm
125478 Pa ----- x
x = 1.2383 atm
d. -17°C → K
K = ºC + 273.15
K = -17 + 273.15
K = 256.15
e. 548 mL → L
V = 548 / 1000
V = 0.548 L