Suhu kota palu = x
20 ≤ x ≤ 32
rumus Celsius ke fahrenheit :
F-32 : C = 9:5
F - 32 = C . 9:5
F = C . 9:5 + 32
untuk 20 :
F = 20. 9:5 + 32
= 4.9 + 32
= 36+32
F = 68°F
untuk 32 :
F = 32 . 9:5 + 32
= 32(9:5 + 1)
= 32(9:5 + 5:5)
= 32(13:5)
= 32.13(1:5)
= (30+2)(10+3)1:5
= (300+90+20+6)1:5
= 416:5
= 83,2°F
maka batas suhu nya jadi :
68°F ≤ x ≤ 83,2°F
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Suhu kota palu = x
20 ≤ x ≤ 32
rumus Celsius ke fahrenheit :
F-32 : C = 9:5
F - 32 = C . 9:5
F = C . 9:5 + 32
untuk 20 :
F = 20. 9:5 + 32
= 4.9 + 32
= 36+32
F = 68°F
untuk 32 :
F = 32 . 9:5 + 32
= 32(9:5 + 1)
= 32(9:5 + 5:5)
= 32(13:5)
= 32.13(1:5)
= (30+2)(10+3)1:5
= (300+90+20+6)1:5
= 416:5
= 83,2°F
maka batas suhu nya jadi :
68°F ≤ x ≤ 83,2°F