Question

Rasionalkan penyebutnya.
Mohon bantuan.

Answer 1

 √3 = √3 x √5  = √15
√5    √5 x √5        5

ini untuk yang no 1 yang lainnya caranya sama.. tinggal di utak atik sendiri

Answer 2

1)
√3/√5 x √5/√5
= √15/5
= 1/5 √15

2)
2a/√(2a) x √(2a)/√(2a)
= 2a√2a / 2a
= √2a

3)
7/(7-√6) x (7+√6)/(7+√6)
= (49+7√6)/(49-6)
= (49+7√6)/43
= 1/43 (49+7√6)

4)
√5/(3+√2) x (3-√2)/(3-√2)
= (3√5 - √10)/(9-2)
= (3√5 - √10)/7
= 1/7 (3√5 - √10)

5)
(3+√5)/(3-√5) x (3+√5)/(3+√5)
= (9+3√5+3√5+5)/(9-5)
= (14+6√5)/4
= (7+3√5)/2
= 1/2 (7+3√5)

6)
(√5-√3)/(√5+√3) x (√5-√3)/(√5-√3)
= (5-√15-√15+3)/(5-3)
= (8-2√15)/2
= 4-√15

7)
8/(8+√5) x (8-√5)/(8-√5)
= (64-8√5)/(64-5)
= (64-8√5)/59
= 1/59 (64-8√5)

8)
√10/(√5+√10) x (√5-√10)/(√5-√10)
= (√50 - 10)/(5-10)
= (√(25.2) - 10)/(-5)
= (5√2 - 10)/(-5)
= -√2 + 2
atau
= 2-√2

9)
(2+√5)/(2-√5) x (2+√5)/(2+√5)
= (4+2√5+2√5+5)/(4-5)
= (9+4√5)/(-1)
= -9-4√5
atau
= -(9+4√5)

10)
(√6-√5)/(√6+√5) x (√6-√5)/(√6-√5)
= (6-√30-√30+5)/(6-5)
= (11-2√30)/1
= 11-2√30

11)
(√2+√5)/(1-√5) x (1+√5)/(1+√5)
= (√2+√10+√5+5)/(1-5)
= (5+√2+√5+√10)/(-4)
= -1/4 (5+√2+√5+√10)

12)
(√7-√5)/(3+√7) x (3-√7)/(3-√7)
= (3√7 - 7 - 3√5 + √35)/(9-7)
= (√35 - 3√5 + 3√7 - 7)/2
= 1/2 (√35 - 3√5 + 3√7 - 7)