Respuesta:
[tex]65d \: {m}^{3} →L= 65 \\ \\ 50 \: {m}^{3} →d {m}^{3} = 50.000 \\ \\ 250 \: L→ {m}^{3} = 0.25 \\ \\ 0,3 \: {dm}^{3} →mL = 3.000 \\ \\ 870 \: cL→ {m}^{3} = 0.0087[/tex]
Explicación:
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Respuesta:
[tex]65d \: {m}^{3} →L= 65 \\ \\ 50 \: {m}^{3} →d {m}^{3} = 50.000 \\ \\ 250 \: L→ {m}^{3} = 0.25 \\ \\ 0,3 \: {dm}^{3} →mL = 3.000 \\ \\ 870 \: cL→ {m}^{3} = 0.0087[/tex]
Explicación: