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Tf⁰ = 0⁰C
V = 600 mL → m = 600 g = 0,6 Kg
ΔTf = 0 - (-1,55)
= 1,55⁰C
ΔTf = m x Kf
1,55 = m x 1,86
m = 0,0833 molal
mol = m x Kg zat pelarut
= 0,0833 x 0,6
= 0,5 mol
massa = mol x Mr
= 0,5 x 62
= 31 gram
Jadi, massa etilen glikol adalah 31 gram