Respuesta:
a)[tex]\frac{1}{\sqrt{3}}=\frac{1}{\sqrt{3}}\times 1=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3}[/tex]
b)[tex]\frac{2}{5\sqrt{7}}=\frac{2\sqrt{7}}{35}[/tex]
c)[tex]7\sqrt{2}/2[/tex]
d)[tex]6\sqrt{3}/3[/tex]
e)[tex]14\sqrt{5}/2[/tex]
f)[tex]2(3-\sqrt{3})/6[/tex]
g)[tex]\sqrt[7]{2^4}/2[/tex]
h)[tex]6 \sqrt[5]{4^3}/28[/tex]
i)[tex](\sqrt{7}-\sqrt{3})/4[/tex]
j)[tex]5(3\sqrt{5}-2)/41[/tex]
k)[tex](3\sqrt{7}+\sqrt{2})/61[/tex]
l)[tex]\sqrt{3}(\sqrt{15}+3)/6[/tex]
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Respuesta:
a)[tex]\frac{1}{\sqrt{3}}=\frac{1}{\sqrt{3}}\times 1=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3}[/tex]
b)[tex]\frac{2}{5\sqrt{7}}=\frac{2\sqrt{7}}{35}[/tex]
c)[tex]7\sqrt{2}/2[/tex]
d)[tex]6\sqrt{3}/3[/tex]
e)[tex]14\sqrt{5}/2[/tex]
f)[tex]2(3-\sqrt{3})/6[/tex]
g)[tex]\sqrt[7]{2^4}/2[/tex]
h)[tex]6 \sqrt[5]{4^3}/28[/tex]
i)[tex](\sqrt{7}-\sqrt{3})/4[/tex]
j)[tex]5(3\sqrt{5}-2)/41[/tex]
k)[tex](3\sqrt{7}+\sqrt{2})/61[/tex]
l)[tex]\sqrt{3}(\sqrt{15}+3)/6[/tex]