Question

Quzkiz
Ayam dulu apa telur dulu?
Gelas minum saya punya diameter 14 cm dan tinggi 16 cm berapakah volume gelas saya?​

Answer 1

Verified answer

Bangun Ruang Sisi Lengkung

[Tabung]

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[tex]\boxed{ \begin{array}{lr} \boxed{\large{\sf{ LP \: = 2 × π × r × (r + t) } }}\\ \boxed{\large{\sf{LP_t = π × r × (r + 2t) \: \: \: \: \: }}} \\ \boxed{\large{\sf{~V ~ \: = π × r \times r × t~~~~~~~~ \: \: } }}\\ \\ \sf{Keterangan \ \: :}\\ \begin{aligned} \sf{ LP} &= \sf{ Luas~Permukaan }\\ \sf{ LP_{t}} &= \sf{ LP ~Tanpa~Tutup} \\ \sf{V} &= \sf{ Volume~Tabung}\\ \sf{ π } &= \sf{Konstanta~Lingkaran }\\\sf{ r} &= \sf{ Jari-Jari~Tabung}\\ \sf{ t} & =\sf{ Tinggi~Tabung }\end{aligned} \end{array}}~~\begin{aligned}& \to~r=½d \\ &\to~π=\frac{22}{7}~Jika~r/d/t = Kelipatan~7 \\ &\to~π=3.14~Jika~r/d/t ≠ Kelipatan~7 \end{aligned}[/tex]

Penyelesaian Soal

[tex]\begin{aligned} Volume~Gelas &= 22/7 × 7~cm × 7~cm × 16~cm \\&= 22~cm × 112~cm² \\&= \boxed{\bold{\underline{2464~cm³}}} \end{aligned}[/tex]

• Ingat! [tex]r=½d[/tex]

[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 18 - 04 - 2023}}[/tex]