QUIZZZZZZZZZZZZZZZZZZ.... Question from @dimas161926

JΟY

${\sf{{}^{\frac{1}{2}}\log6+{}^{\frac{1}{2}}\log5-{}^{\frac{1}{2}}\log12-{}^{\frac{1}{2}}\log10=\textsf{\textbf{2}}}}$

Pembahasan

$\begin{aligned}&{\sf{{}^{\frac{1}{2}}\log6+{}^{\frac{1}{2}}\log5-{}^{\frac{1}{2}}\log12-{}^{\frac{1}{2}}}}\\&={\sf{{}^{2^{-1}}\log6+{}^{2^{-1}}\log5-{}^{2^{-1}}\log12-{}^{2^{-1}}\log10}}\\&={\sf{{}^{2^{-1}}\log\left(\frac{6\times5}{12\times10}\right)}}\\&={\sf{{}^{2^{-1}}\log\left(\frac{30}{120}\right)}}\\&={\sf{{}^{2^{-1}}\log\left(\frac{1}{4}\right)}}\\&={\sf{{}^{2^{-1}}\log\left(\frac{1}{2^2}\right)}}\\&={\sf{{}^{2^{-1}}\log\left(2^{-2}\right)}}\\&={\sf{{}^{2^{-1}}\log\left(2^{-1}\right)^2}}\\&={\sf{2\cdot{}^{2^{-1}}\log2^{-1}}}\\&={\sf{2\cdot1}}\\&={\sf{2}}\end{aligned}$

1 votes Thanks 0

BNP999

Penjelasan dengan langkah-langkah:

½log(6) + ½log(5) - ½log(12) - ½log(10)

½ log(6.5) - ( ½log(12) + ½log(10)

½log(30) - ½log(12.10)

½log(30/120)

½log(30(1)/30(4))

½log(¼)

2^-1 log(4^-1)

2^-1 log(2²)^-1

2^-1 log2^-2

(-2)/(-1) . ²log(2)

0 votes Thanks 0

Pembahasan

Recommend Questions

Life Enjoy

Get in touch

Social