f(x) = x! - x! + 100
f(3) = 100
f(3) = 3! - 3! + 100
f(3) = (3 × 2 × 1) - (3 × 2 × 1) + 100
f(3) = (6 × 1) - (6 × 1) + 100
f(3) = 6 - 6 + 100
f(3) = 0 + 100
Mapel:Matematika
Kelas:10 - SMA
Materi:Bab 1 - Eksponen dan logaritma
Kata kunci:Eksponen,Faktorial,Pengurangan,Pertambahan
Kode:10.2.1
f(x) = (3 × 2) - (3 × 2) + 100
f(x) = 6 - 6 + 100
f(x) = 0 + 100
f(x) = 100
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Jawaban:
f(x) = x! - x! + 100
f(3) = 100
Pembahasan:
f(x) = x! - x! + 100
f(3) = 3! - 3! + 100
f(3) = (3 × 2 × 1) - (3 × 2 × 1) + 100
f(3) = (6 × 1) - (6 × 1) + 100
f(3) = 6 - 6 + 100
f(3) = 0 + 100
f(3) = 100
Detail:
Mapel:Matematika
Kelas:10 - SMA
Materi:Bab 1 - Eksponen dan logaritma
Kata kunci:Eksponen,Faktorial,Pengurangan,Pertambahan
Kode:10.2.1
~Jawaban~
f(x) = x! - x! + 100
f(x) = (3 × 2) - (3 × 2) + 100
f(x) = 6 - 6 + 100
f(x) = 0 + 100
f(x) = 100
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