Question

Quiz Malam part 1
( p + 2 )⁶
Beserta caranya ​

Answer 1

Verified answer

[tex] {(p + 2)}^{6} = [/tex]

[tex](p + 2)(p + 2)(p + 2)(p + 2)(p + 2)(p + 2) = [/tex]

[tex]((p + 2)(p + 2))((p + 2)(p + 2))((p + 2)(p + 2)) = [/tex]

[tex](p(p + 2) + 2(p + 2))(p(p + 2) + 2(p + 2))(p(p + 2) + 2(p + 2)) = [/tex]

[tex]( {p}^{2} + 2p + 2p + 4)( {p}^{2} + 2p + 2p + 4)( {p}^{2} + 2p + 2p + 4) = [/tex]

[tex]( {p}^{2} + 4p + 4) ({p}^{2} + 4p + 4)( {p}^{2} + 4p + 4) = [/tex]

[tex](( {p}^{2} + 4p + 4)( {p}^{2} + 4p + 4))( {p}^{2} + 4p + 4) = [/tex]

[tex]( {p}^{2} ( {p}^{2} + 4p + 4) + 4p ( {p}^{2} + 4p + 4) + 4( {p}^{2} + 4p + 4))( {p}^{2} + 4p + 4) = [/tex]

[tex]( {p}^{4} + 4 {p}^{3} + 4 {p}^{2} + 4 {p}^{3} + 16 {p}^{2} + 16p + 4 {p}^{2} + 16p + 16)( {p}^{2} + 4p + 4) = [/tex]

[tex]( {p}^{4} + 8 {p}^{3} + 24 {p}^{2} + 32p + 16)( {p}^{2} + 4p + 4) = [/tex]

[tex] {p}^{4} ({p}^{2} + 4p + 4) + 8 {p}^{3} ( {p}^{2} + 4p + 4) + 24 {p}^{2} ( {p}^{2} + 4p + 4) + 32p( {p}^{2} + 4p + 4) + 16( {p}^{2} + 4p + 4) = [/tex]

[tex] {p}^{6} + 4 {p}^{5} + 4 {p}^{4} + 8 {p}^{5} + 32 {p}^{4} + 32 {p}^{3} + 24 {p}^{4} + 96 {p}^{3} + 96 {p}^{2} + 32 {p}^{3} + 128 {p}^{2} + 128p + 16 {p}^{2} + 64p + 64 = [/tex]

[tex] {p}^{6} + 12 {p}^{5} + 60 {p}^{4} + 160 {p}^{3} + 240 {p}^{2} + 192p + 64[/tex]