Jawaban:
No 1).
s =
s = 15 cm
Volume:
V = s × s × s
V = 15 × 15 × 15
V = 3.375 cm³
Luas permukaan:
L = 6 × s × s
L = 6 × 15 × 15
L = 1.350 cm²
No 2).
tinggi balok:
t = V : (p × l)
t = 288 : (12 × 2)
t = 288 : 24
t = 12 cm
L = 2 × ((p × l) + (p × t) + (l × t))
L = 2 × ((12 × 2) + (12 × 12) + (2 × 12))
L = 2 × (24 + 144 + 24)
L = 2 × 192
L = 384 cm²
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Jawaban:
No 1).
s =
s =
s = 15 cm
Volume:
V = s × s × s
V = 15 × 15 × 15
V = 3.375 cm³
Luas permukaan:
L = 6 × s × s
L = 6 × 15 × 15
L = 1.350 cm²
No 2).
tinggi balok:
t = V : (p × l)
t = 288 : (12 × 2)
t = 288 : 24
t = 12 cm
Luas permukaan:
L = 2 × ((p × l) + (p × t) + (l × t))
L = 2 × ((12 × 2) + (12 × 12) + (2 × 12))
L = 2 × (24 + 144 + 24)
L = 2 × 192
L = 384 cm²