(3 , 0) dan (0 , 2)
x1 = 3 dan y1 = 2
(y1)x + (x1)y = (x1)(y1)
2x + 3y = (3)(2)
2x + 3y = 6
2x + 3y - 6 = 0
a = 2
b = 3
c = -6
a + b + c
= 2 + 3 + (-6)
= 5 - 6
= -1 (A)
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(3 , 0) dan (0 , 2)
x1 = 3 dan y1 = 2
(y1)x + (x1)y = (x1)(y1)
2x + 3y = (3)(2)
2x + 3y = 6
2x + 3y - 6 = 0
a = 2
b = 3
c = -6
a + b + c
= 2 + 3 + (-6)
= 5 - 6
= -1 (A)
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