Question

Quis

f(x) = √x + 5² - 10² + 3!
f(4) = ...*

Pake Cara

Note ; Om ARZEM ​

Answer 1

Penyelesaian :

f(x) = √x + 5² - 10² + 3!

f(4) = √4 + 5² - 10² + 3!

f(4) = 2 + 5² - 10² + 3!

f(4) = 2 + ( 5 × 5 ) - 10² + 3!

f(4) = 2 + 25 - 10² + 3!

f(4) = 2 + 25 - ( 10 × 10 ) + 3!

f(4) = 2 + 25 - 100 + 3!

f(4) = 2 + 25 - 100 + ( 3 × 2 × 1 )

f(4) = 2 + 25 - 100 + ( 6 × 1 )

f(4) = 2 + 25 - 100 + 6

f(4) = 27 - 100 - 6

f(4) = ( -73 ) - 6

f(4) = ( -79 )

Answer 2

»Fungsi Komposisi

→Menyederhanakan f(x)

f(x) = √x + 5² - 10² + 3!

f(x) = √x + 25 - 100 + 6

f(x) = √x - 69

→Mencari nilai f(4)

f(4) = √4 - 69

f(4) = 2 - 69

f(4) = -67