[tex]co {}^{2} = h {}^{2} - ca {}^{2} \\ co {}^{2} = 20 {}^{2} - 11 {}^{2} \\ co {}^{2} = 400 - 121 \\ co {}^{2} = 279 \\ co = \sqrt{279} \\ co = \sqrt{3 {}^{2} } \sqrt{31} \\ co = 3 \sqrt{31} [/tex]
[tex]5k = 15 \\ k = \frac{15}{5} \\ k = 3[/tex]
[tex]ca = 4k \\ ca = 4(3) \\ ca = 12[/tex]
[tex]co = 3k \\ co = 3(3) \\ co = 9[/tex]
Espero ayudar!!
saludos
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1)
✅ Teorema de pitágoras :
[tex]co {}^{2} = h {}^{2} - ca {}^{2} \\ co {}^{2} = 20 {}^{2} - 11 {}^{2} \\ co {}^{2} = 400 - 121 \\ co {}^{2} = 279 \\ co = \sqrt{279} \\ co = \sqrt{3 {}^{2} } \sqrt{31} \\ co = 3 \sqrt{31} [/tex]
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2)
✅ Triángulo notable de 37° y 53° :
[tex]5k = 15 \\ k = \frac{15}{5} \\ k = 3[/tex]
➡️ El valor de "ca" :
[tex]ca = 4k \\ ca = 4(3) \\ ca = 12[/tex]
➡️ El valor de "co" :
[tex]co = 3k \\ co = 3(3) \\ co = 9[/tex]
Espero ayudar!!
saludos