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¹⁶√[(3)(5)(17)(257) + 1] = ( El 3 = 4 - 1 , El 5 = 4 +1
¹⁶√[(4 - 1)(4 + 1)(17)(257) +1] = Aplicas productos notables (a + b)(a - b)
a² - b²
¹⁶√[(4² - 1²)(17)(257) + 1] = ( El 17 = 16 + 1)
¹⁶√[(16 - 1)(16 + 1)(257) + 1] =
¹⁶√[(16² - 1)(257) + 1] = (257 = 256 + 1 = 16² + 1)
¹⁶√(256 - 1)(256+ 1) + 1] =
¹⁶√(256² - 1 + 1) =
¹⁶√(256)² =
256 2(mitad)
128 2 ,,,,,,,,,,,
64 2,,,,,,,,,,,,
32 2,,,,,,......
16 2,,,,,,,,,,,,
8 2,,,,,,,,,,,
4 2,,,,,,,,,,,
2 2,,,,,,,,,,
1
256 = 2*2*2*2*2*2*2*2 = 2⁸
¹⁶√(256)² =
¹⁶√(2⁸)² =
¹⁶√2¹⁶ =
2¹⁶/¹⁶ =
2
Respuesta.
¹⁶√[(3)(5)(17)(257) + 1] = 2