qual es el valor numerico de 2x^5+x^4-2x^2-5\:cuando\:x=-1 y de y^3+3y^2-5\:cuando\:x=3
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Respuesta:
la primera es -8
la segunda es 49
Explicación paso a paso:
2x⁵ + x⁴ - 2x² - 5 ----> x = -1
2 (-1)⁵ + (-1)⁴ - 2 (-1)² - 5 = 2 * (-1) + (1) - 2 * (1) - 5 = -2 + 1 - 2 - 5 = -8
y³ + 3y² - 5 ----> x = 3
(3)³ + 3 * (3)² - 5 = 27 + 3 * 9 - 5 = 27 + 27 - 5 = 49