Question

Q.
tentukan hasil dari 3 + 4 + 5 .... + 102 = ... ?​

Answer 1

a = 3

b = 1

Un = 102

.

• Mencari Un

Un = a + (n - 1)b

Un = a + n(1) + (-1)(1)

Un = a + n - 1

• Mencari n

→ Un = a + n - 1

→ 102 = 3 + n - 1

→ 102 - 3 + 1 = n

→ 100 = n

→ n = 100

• Hasil dari 3 + 4 + 5 .... + 102

[tex] \tt S_{n} = \frac{n}{2} (2a + Un) [/tex]

[tex] \tt S_{100} = \frac{100}{2} (2(3) + 102) [/tex]

[tex] \tt S_{100} = 50(6 + 102) [/tex]

[tex] \tt S_{100} = 50(108) [/tex]

[tex] \tt S_{100} = 5.400 [/tex]

.

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Answer 2

Penjelasan dengan langkah-langkah:

3 + 4 + 5 .... + 102 = ... ?

Un = a + (n - 1).b

= a + n - 1

nilai n

Un = a + n - 1

102 = 3 + n - 1

102 - 3 + 1 = n

100 = n

SN = n/2(2a + Un )

S100 = 100/2(2.3 + 102)

S100 = 5.400