Question

Diketahui TS//QR. Jika panjang PT=6cm, TQ=15cm, QR=42cm, dan TS=(2x-8)cm, nilai x+4 adalah...cm​

Answer 1

Jawaban:

c.14

Penjelasan dengan langkah-langkah:

TS dan QR sejajar

PT = 6cm

TQ = 15cm

QR = 42cm

TS = (2x - 8)

PQ/PT = QR/TS

21/6 = 42/2x-8

(6×42÷21 = 12)

12 = 2x-8

2x+8 = 10

x = 10

x + 4 = 14