Question

Q.

Persamaan garis yang melewati (-2,1) dan tegak lurus dengan garis (-5,-4) dan (0,-2) adalah..​

Answer 1

SOAL 1___________________________________________ Persamaan Garis (-5,-4) Dan (0,-2) : y - y1/y2 - y1 = x - x1/x2 - x1y - (-4)/-2 - (-4) = x - (-5)/0 - (-5)y + 4/-2 + 4 = x + 5/0 + 5y + 4/2 = x + 5/55y + 20 = 2x + 105y = 2x + 10 - 205y = 2x - 10y = 2/5x - 10 m1 → 2/5 ___________________________________________ Gradien : m1 × m2 = -12/5 × m2 = -1m2 = -1 ÷ 2/5m2 = -1 × 5/2m2 = -5/2 ___________________________________________ Persamaan Garis (-2,1) : y - y1 = m(x - x1) y - 1 = -5/2(x - (-2))y - 1 = -5/2(x + 2)2y - 2 = -5(x + 2) 2y - 2 = -5x - 105x + 2y = -10 + 2 5x + 2y = -8 , 5x + 2y + 8 = 0 ___________________________________________ [tex] {\mathcal\color{purple}{{\pink{\underline{\purple{\underline\bold{\pink{K}\bold\color{violet}{h\bold{\pink{a}\bold\color{violet}{d\bold{\pink{i}\bold\color{violet}{j\bold{\pink{a}\bold\color{violet}{h\bold{\pink{A}\bold\color{violet}{m\bold{\pink{j}\bold\color{violet}{a\bold{\pink{d}\bold\color{violet}{1\bold{\pink{2}}}}}}}}}}}}}}}}}}}}}}[/tex]