LOgaritma
ᵃlog aⁿ = n
ᵃlog b × ᵇlog aⁿ = n
__
²log 8 + ³log 4 × ⁴log 27
= ²log 2³ + ³log 27
= 3 + ³log 3³
= 3 + 3
= 6
Jawaban:
logaritma
a log(a) = 1
a log(n) x ⁿlog(b) = a log(b)
maka:
²log(8) + {³log(4) x ⁴log(27)} = ²log(2³) + { ³log(27) } = 3 . ²log(2) + ³log(3³) = 3 . 1 + 3 . ³log(3) = 3 + 3.1 = 3+3 = 6
jadi, hasil dari ²log(8) + { ³log(4) x ⁴log(27) } adalah 6.
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Verified answer
LOgaritma
ᵃlog aⁿ = n
ᵃlog b × ᵇlog aⁿ = n
__
²log 8 + ³log 4 × ⁴log 27
= ²log 2³ + ³log 27
= 3 + ³log 3³
= 3 + 3
= 6
Jawaban:
logaritma
a log(a) = 1
a log(n) x ⁿlog(b) = a log(b)
maka:
²log(8) + {³log(4) x ⁴log(27)} = ²log(2³) + { ³log(27) } = 3 . ²log(2) + ³log(3³) = 3 . 1 + 3 . ³log(3) = 3 + 3.1 = 3+3 = 6
jadi, hasil dari ²log(8) + { ³log(4) x ⁴log(27) } adalah 6.