Question

Q

Lim 3x² × 5x! + 2³ × x!!
x => 7

nt : Byeee ;_;​

Answer 1

Jawaban:

Penyelesaian

Lim = 3(7)² × 5(7)! + 2³ × (7)!! =

=3(7 × 7) × 5(7 × 6 × 5 × 4 × 3 × 2) + (2 × 2 × 2)× (7 × 5 × 3)

= (3 × 49) × 5(42 × 5 × 4 × 3 × 2 + (4 × 2) × (35 × 3)

= 147 × 5(210 × 4 × 3 × 2) + ( 8 × 105)

= 147 × 5(840 × 3 × 2) + 840

= 147 × 5(2.520 × 2) + 840

= 147 × (5 × 5.040) + 840

=( 147 × 25.200) + 840

= 3.704.400 + 840

= 3.705.240

Answer 2

jawaban:

3.705.240

Penjelasan dengan langkah-langkah:

Lim 3x² × 5x! + 2³ × x!!

Lim 3x² × 5x! + 2³ × x!!x => 7

= 3x² × 5x! + 2³ × x!!

= 3(7²) × 5(7!) + 2³ × 7!!

= 3(7×7) × 5(7×6×5×4×3×2×1) + (2×2×2) × (7×5×3×1)

= 3(49) × 5(5.040) + (8×105)

= 147 × 25.200 + 840

= 3.704.500 + 840

= 3.705.240

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