Q.ikan
1.) 2023² - 2024² = ..
2.) f(x) = 6x² + 4x³ + 7x
f'(4) = ..
______________
Kebanyakan Off BeA +500 Ludes ilang :v
1.) 2023² - 2024² = ..
2.) f(x) = 6x² + 4x³ + 7x
f'(4) = ..
______________
Kebanyakan Off BeA +500 Ludes ilang :v
[Nomor 1]
2023² - 2024²
= (2023 + 2024)(2023 - 2024)
= (4047)(-1)
= -4047
[Nomor 2]
f(x) = 6x² + 4x³ + 7x
f'(x) = 2(6x²-¹) + 3(4x³-¹) + 7
f'(x) = 12x + 12x² + 7
f'(4) = 12(4) + 12(4)² + 7
f'(4) = 48 + 12(16) + 7
f'(4) = 48 + 192 + 7
f'(4) = 247
2023² - 2024²
( 2.023 × 2023 ) - ( 2024 × 2024 )
4.092.529 - 4.096.576
-4047
__________________
f(x) = 6x² + 4x³ + 7x
f'(x) = (2×6)x^(2-1) + (4×3)x^(3-1) + 7x^(1-1)
f'(x) = 12x¹ + 12x² + 7x^0
f'(x) = 12x + 12x² + 7(1)
f'(x) = 12x + 12x² + 7
f'(4) = 12(4) + 12(4²) + 7
f'(4) = 48 + 12(16) + 7
f'(4) = 48 + 192 + 7
f'(4) = 240 + 7
f'(4) = 247