Q.
f(x) = x²(x) - x²(2)
f(5) =
nothing
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f(x) = x²(x) - x²(2)
f(5) =
nothing
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f(x) = x²(x) - x²(2)
f(5) = 5²(5) - 5²(2)
f(5) = (5 × 5)(5) - (5 × 5)(2)
f(5) = 25(5) - 25(2)
f(5) = 125 - 50
f(5) = 75
Ninmy!
f(x) = x²(x) - x²(2)
f(5) = ...
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f(5) = 5²(5) - 5²(2)
f(5) = 5.5(5) - 5.5(2)
f(5) = 25(5) - 25(2)
f(5) = 125 - 50
f(5) = 75