Question

Q.

f(x) = x³ × 5³ + x!!
f(9) = ?
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No ngasal!!
No copas!!
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Answer 1

JAWABAN

Penyelesaian :

→ f(x) = x³ × 5³ + x!!

→ f(9) = 9³ × 5³ + 9!!

→ f(9) = ( 9 × 9 × 9 ) × 5³ + 9!!

→ f(9) = ( 81 × 9 ) × 5³ + 9!!

→ f(9) = 729 × ( 5 × 5 × 5 ) + 9!!

→ f(9) = 729 × ( 25 × 5 ) + 9!!

→ f(9) = 729 × 125 + 9!!

→ f(9) = 729 × 125 + ( 9 × 7 × 5 × 3 × 1 )

→ f(9) = 729 × 125 + ( 63 × 5 × 3 × 1 )

→ f(9) = 729 × 125 + ( 315 × 3 × 1 )

→ f(9) = ( 729 × 125 ) + 945

→ f(9) = 91.125 + 945

→ f(9) = 92.070

I Hope This Help-!

Answer 2

SOAL 1

f(x) = x³ × 5³ + x!!

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9!!

= 9 × 7 × 5 × 3 × 1

= 63 × 5 × 3 × 1

= 315 × 3 × 1

= 945 × 1

= 945

f(9) = 9³ × 5³ + 9!!

f(9) = (9 × 9 × 9) × (5 × 5 × 5) + 945

f(9) = (81 × 9) × (25 × 5) + 945

f(9) = 729 × 125 + 945

f(9) = 91.125 + 945

f(9) = 92.070

UwU