f(x) = x!! - 20 + 2x
f(5) = 5!! - 20 + 2(5)
f(5) = ( 5 × 3 × 1 ) - 20 + 2(5)
f(5) = ( 15 × 1 ) - 20 + 2(5)
f(5) = 15 - 20 + 2(5)
f(5) = 15 - 20 + ( 2 × 5 )
f(5) = 15 - 20 + 10
f(5) = ( - 5 ) + 10
f(5) = 5
12²
12 × 12
= 144
Jawaban:
=> 1
f(5) = 5!! - 20 + ( 2.5 )
f(5) = ( 5.3.1 ) - 20 + ( 2.5 )
f(5) = ( 15.1 ) - 20 + ( 2.5 )
f(5) = -5 + 10
___
=> 2
= 12 × 12
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f(x) = x!! - 20 + 2x
f(5) = 5!! - 20 + 2(5)
f(5) = ( 5 × 3 × 1 ) - 20 + 2(5)
f(5) = ( 15 × 1 ) - 20 + 2(5)
f(5) = 15 - 20 + 2(5)
f(5) = 15 - 20 + ( 2 × 5 )
f(5) = 15 - 20 + 10
f(5) = ( - 5 ) + 10
f(5) = 5
__________________________
12²
12 × 12
= 144
Jawaban:
=> 1
f(x) = x!! - 20 + 2x
f(5) = 5!! - 20 + ( 2.5 )
f(5) = ( 5.3.1 ) - 20 + ( 2.5 )
f(5) = ( 15.1 ) - 20 + ( 2.5 )
f(5) = 15 - 20 + 10
f(5) = -5 + 10
f(5) = 5
___
=> 2
12²
= 12 × 12
= 144
___