Question

Q.

f(x) = 3x³ + 4x² - 2x + 7 - 3
f(3b + 2) = ..*

Genepin bsk 50 dan g akan buat soal lagi :b
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Answer 1

f(x) = 3x³ + 4x² - 2x + 7 - 3

f(x) = 3x³ + 4x² - 2x + 4

f(3b + 2) = 3 ( 3b + 2 )³ + 4 ( 3b + 2 )² + 2 ( 3b + 2 ) + 4

f(3b + 2) = 3 ( ( 3b + 2 ) ( 3b + 2 )² ) + 4 ( ( 3b + 2 ) ( 3b + 2 ) ) + 6b + 4

f(3b + 2) = 3 ( ( 9b² + 6b + 6b + 4 ) ( 3b + 2 ) ) + ( 9b² + 6b + 6b + 4 ) + 6b + 4

f(3b + 2) = 3 ( ( 9b² + 12b + 4 ) ( 3b + 2 ) ) + ( 9b² + 12b + 4 ) + 6b + 4

f(3b + 2) = 3 ( ( 9b² ( 3b + 2 ) + 12b ( 3b + 2 ) + 4 ( 3b + 2 ) + ( 9b² + 12b ) + 6b + 4

f(3b + 2) = 3 ( 27b³ + 18b² + 36b² + 24b + 12b + 8 ) + ( 9b² + 12b ) + 6b + 4

f(3b + 2) = 81b³ + 54b² + 108b² + 72b + 36b + 24 + 9b² + 12b + 6b + 4

f(3b + 2) = 81b³ + 54b² + 108b + 24 + 9b² + 18b + 4

f(3b + 2) = 81b³ + 54b² + 9b² + 108b + 18b + 24 + 4

f(3b + 2) = 81b³ + 63b² + 126b + 28

Answer 2

Penjelasan dengan langkah-langkah:

f(x) = 3x³ + 4x² - 2x + 7 - 3

f(x) = x(3x² + 4x – 2) + 4

f(x) = x(x(3x + 4) – 2) + 4

f(3b + 2) = (3b + 2)(3b + 2)(3(3b + 2) + 4) – 2) + 4

f(3b + 2) = (3b + 2)(3b + 2)(9b + 6 + 4 – 2) + 4

f(3b + 2) = (3b + 2)(3b + 2)(9b + 8) + 4

f(3b + 2) = (9b² + 12b + 4)(9b + 8) + 4

f(3b + 2) = 81b³ + 72b² + 108b² + 96b + 32 + 4

f(3b + 2) = 81b³ + 180b² + 96b + 36

f(3b + 2) = 3(27b³ + 60b² + 32b + 12)

f(3b + 2) = 3(3b²(9b + 20) + 4(8b + 3))