f(i + a) = 4a + 2i x 1a
f(i + a) = ...
_
i = 4
a = 3
f(i + a) = 4a + 2i × 1a
f(4 + 3) = 4(3) + 2(4) × 1(3)
f(7) = 12 + 8 × 3
f(7) = 12 + 24
f(7) = 36
#koreksii
f(7) = ( 4 × 3 ) + ( 2 × 4 ) × ( 1 × 3 )
f(7) = 12 + ( 8 × 3 )
koreksi
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
f(i + a) = 4a + 2i x 1a
f(i + a) = ...
_
i = 4
a = 3
_
f(i + a) = 4a + 2i × 1a
f(4 + 3) = 4(3) + 2(4) × 1(3)
f(7) = 12 + 8 × 3
f(7) = 12 + 24
f(7) = 36
#koreksii
f(i + a) = 4a + 2i × 1a
f(4 + 3) = 4(3) + 2(4) × 1(3)
f(7) = ( 4 × 3 ) + ( 2 × 4 ) × ( 1 × 3 )
f(7) = 12 + 8 × 3
f(7) = 12 + ( 8 × 3 )
f(7) = 12 + 24
f(7) = 36
koreksi