Question

Q.

f(c) = 5c + 6(c + c)
f(1) = ..
f(3) = ..
f(6) = ..
​

Answer 1

Diketahui

f(c) = 5c + 6( c + c )

Ditanya

f(1) = ?

f(3) = ?

f(6) = ?

Jawab :

f(c) = 5c + 6( c + c )

f(1) = 5(1) + 6( 1 + 1 )

f(1) = 5(1) + 6(2)

f(1) = ( 5 × 1 ) + 6(2)

f(1) = 5 + ( 6 × 2 )

f(1) = 5 + 12

Kesimpulan c → 1 = 17

f(c) = 5c + 6( c + c )

f(3) = 5(3) + 6( 3 + 3 )

f(3) = 5(3) + 6(6)

f(3) = ( 5 × 3 ) + ( 6 × 6 )

f(3) = 15 + 36

Kesimpulan c → 3 = 51

f(c) = 5c + 6( c + c )

f(6) = 5(6) + 6( 6 + 6 )

f(6) = 5(6) + 6(12)

f(6) = ( 5 × 6 ) + ( 6 × 12 )

f(6) = 30 + 72

Kesimpulan c → 6 = 102

Answer 2

Langkah – Langkah :

→ f(1)

f(c) = 5c + 6(c + c)

f(1) = 5(1) + 6( 1 + 1 )

f(1) = 5(1) + 6(2)

f(1) = 5 + 6(2)

f(1) = 5 + 12

f(1) = 17

•••••••••••••••••

→ f(3)

f(c) = 5c + 6(c + c)

f(3) = 5(3) + 6( 3 + 3 )

f(3) = 5(3) + 6(6)

f(3) = 15 + 6(6)

f(3) = 15 + 36

f(3) = 51

•••••••••••••••

→f(6)

f(c) = 5c + 6(c + c)

f(6) = 5(6) + 6( 6 + 6 )

f(6) = 5(6) + 6(12)

f(6) = 30 + 6(12)

f(6) = 30 + 72

f(6) = 102

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