Odpowiedź:
-->
BC = [ 5 - ( - 1 ), - 3 - 1 ] = [ 6, - 4 ]
D = ( x , y )
więc
--> -->
AD = [ x - ( - 5 ) , y - ( - 2) ] = [ x + 5, y + 2 ] = BC
[ x + 5, y + 2 ] = [6 , - 4 ]
x + 5 = 6 y + 2 = - 4
x = 1 y = - 6
D = ( 1 , - 6 )
==============
S = ( [tex]\frac{- 5 + 5}{2} , \frac{-2 - 3}{2}[/tex] ) = ( 0 , - 2,5 )
===============================
S - środek AC
Szczegółowe wyjaśnienie:
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Odpowiedź:
-->
BC = [ 5 - ( - 1 ), - 3 - 1 ] = [ 6, - 4 ]
D = ( x , y )
więc
--> -->
AD = [ x - ( - 5 ) , y - ( - 2) ] = [ x + 5, y + 2 ] = BC
więc
[ x + 5, y + 2 ] = [6 , - 4 ]
x + 5 = 6 y + 2 = - 4
x = 1 y = - 6
D = ( 1 , - 6 )
==============
S = ( [tex]\frac{- 5 + 5}{2} , \frac{-2 - 3}{2}[/tex] ) = ( 0 , - 2,5 )
===============================
S - środek AC
Szczegółowe wyjaśnienie: