Przedmiot umieszczono w odlegloci 40 cm od soczewki skupiajacej o ogniskowej 20cm. oblicz w jakiej o.... Question from @Kasienka2701

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Przedmiot umieszczono w odlegloci 40 cm od soczewki skupiajacej o ogniskowej 20cm. oblicz w jakiej odleglosci od soczewki powstanie obraz, powiekszenie obrazu, wypisz cechy obrazu.

Edycia93 Dane;
x=40cm
f=20 cm
szukane;
p=?
y=?
wzór;
1/f=1/x+1/y
p=y/x
rozwiązanie;
1/20cm=1/40cm+1/y
1/y=1/40
y=40cm
p=40cm/40cm=1cm
odp; powiekszenie obrazu wynosi 1 cm, zaś odległość obrazu od soczewki wynosi 40cm;)
a obraz będzie rzeczywisty i takiej samej wielkości;)

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