Odpowiedź:
[tex]\displaystyle \frac{x+5}{x-2} =\frac{x+1}{x} \qquad x\neq 2\quad x\neq 0\\(x-2)(x+1)=x(x+5)\\x^{2} +x-2x-2=x^{2} +5x\\-6x=2/:(-6)\\x=-\frac{2}{6} =-\frac{1}{3}[/tex]
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Odpowiedź:
[tex]\displaystyle \frac{x+5}{x-2} =\frac{x+1}{x} \qquad x\neq 2\quad x\neq 0\\(x-2)(x+1)=x(x+5)\\x^{2} +x-2x-2=x^{2} +5x\\-6x=2/:(-6)\\x=-\frac{2}{6} =-\frac{1}{3}[/tex]