Odpowiedź:
[tex]\displaystyle \frac{\frac{x-2,6}{3} -2x}{4} \ge\frac{x+2}{5} /\cdot 20\\5\left(\frac{x-2,6}{3} -2x\right)\ge4(x+2)\\\frac{5x-13}{3} -10x\ge4x+8/\cdot3\\5x-13-30x\ge12x+24\\-37x\ge37/:(-37)\\x\le-1[/tex]
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Odpowiedź:
[tex]\displaystyle \frac{\frac{x-2,6}{3} -2x}{4} \ge\frac{x+2}{5} /\cdot 20\\5\left(\frac{x-2,6}{3} -2x\right)\ge4(x+2)\\\frac{5x-13}{3} -10x\ge4x+8/\cdot3\\5x-13-30x\ge12x+24\\-37x\ge37/:(-37)\\x\le-1[/tex]