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CaCl2= 40u+35u*2=110u
CuCO3=64u+12u+3*16u=124u
Ni(NO3)2=59u+2*14u+6*16u=183u
(NH4)3PO4=3*14u+12u+31u+4*16u=149u
zad9
Masa całego związku AlCl3=132u
Al%=27u*100%/132u=20%
Cl=105*100%/132u=79,5%