Question

prosze o pomoc nvvhhh

Answer 1

Odpowiedź:

[tex]25^{1 - log_5 2} = 25*25^{- log_5 2} = 25*( 5^2)^{- log_5 2} = 25*5^{ - 2 log_5 2} =[/tex]

[tex]= 25*5^{log_5 2^{-2}} = 25*\frac{1}{4} = \frac{25}{4} = 6,25[/tex]

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1)  [tex]36^{log_6 4} = ( 6^2)^{log_6 4} = 6^{2log_6 4} = 6^{log_6 4^2} = 4^2 = 16[/tex]

2 )  [tex]27^{log_3 64} = ( 3^3)^{log_3 64} = 3^{3 log_3 64} = 3^{log_3 64^3} = 64^3[/tex]

3 ) [tex]3^{2 + log_3 5} = 3^2*3^{log_3 5} = 9*5 = 45[/tex]

4 )  [tex]16^{1 - log_2 3} = 16^1 *16^{- log_2 3} = 16* (2^4)^{-log_2 3} = 16*2^{-4 log_2 3} =[/tex]

[tex]= 16*2^{log_2 3^{-4}} = 16*3^{-4} = 16*\frac{1}{3^4} = \frac{16}{81}[/tex]

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