Question

prosze na teraz dam naj​

Answer 1

Verified answer

[tex]P_{1}[/tex] - ten wyżej trójkąt

[tex]P_{2}[/tex] - ten niżej trójkąt

[tex]h_{1}= \frac{4}{2}[/tex]cm

[tex]a_{1} =7[/tex]cm

[tex]P_{1}=\frac{ah}{2} \\P_{1}=\frac{7*2}{2} \\P_{1}=7cm^{2}[/tex]

[tex]h_{2} =\frac{7}{2} cm[/tex]

[tex]a_{2} =4cm[/tex]

[tex]P_{2}=\frac{ah}{2}\\P_{2}=\frac{2,5*4}{2} \\P_{2}=5cm^{2}[/tex]