Question

Prosze na szybko potrzebuję na jutro. Daję 20+ punktów, naj i serduszko (Zadanie 3) klasa 1 matfiz

Answer 1

Odpowiedź:

Szczegółowe wyjaśnienie:

[tex]x = \frac{3}{2} , y = -\frac{1}{4} , z = -\frac{3}{8}\\\\[/tex]

3a)

[tex]\frac{x - y}{y - z} = \frac{\frac{3}{2} - (-\frac{1}{4}) }{-\frac{1}{4} - (-\frac{3}{8})} = \frac{\frac{6}{4} +\frac{1}{4} }{-\frac{2}{8} + \frac{3}{8}} = \frac{\frac{7}{4} }{\frac{1}{8} } = \frac{7}{4} * 8 = 7 * 2 = 14\\\\[/tex]

3b)

[tex]\frac{x + y - z}{y + z} = \frac{ \frac{3}{2} + (- \frac{1}{4}) - (- \frac{3}{8} )}{ -\frac{1}{4} + (- \frac{3}{8} )} = \frac{ \frac{12}{8} - \frac{2}{8} + \frac{3}{8} }{ -\frac{2}{8} - \frac{3}{8} } = \frac{ \frac{13}{8} }{- \frac{5}{8} } = \frac{13}{8} * (- \frac{8}{5}) = - \frac{13}{5} = (-2,6)\\\\[/tex]

3c)

[tex]\frac{x - y + 2z}{x + y + 3z} = \frac{ \frac{3}{2} - (- \frac{1}{4} ) + 2(- \frac{3}{8} )}{ \frac{3}{2} + (- \frac{1}{4} ) + 3(- \frac{3}{8} )} = \frac{ \frac{6}{4} + \frac{1}{4} - \frac{3}{4} }{ \frac{12}{8} - \frac{2}{8} - \frac{9}{8} } = \frac{ \frac{4}{4} }{- \frac{1}{8} } = 1 * (-8) = (-8)\\\\[/tex]