Odpowiedź:
b ) = [tex]\frac{5,2*1,5*10^{8 -3}}{1,3*10^{18}} = \frac{7,8*10^5}{1,3*10^{18}} = 6*10^{5 - 18} = 6*10^{-13}[/tex]
d ) = [tex]\frac{4,8*1,8*10^{18-10}}{6*1,2*10^{-8+16}} =\frac{8,64*10^8}{7,2*10^8}= 1,2*10^{8-8} = 1,2[/tex][tex]*10^0 = 1,2*1 = 1,2[/tex]
Szczegółowe wyjaśnienie:
[tex]a^m * a^n = a^{m + n}[/tex]
[tex]a^m : a^n = a^{m - n}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
b ) = [tex]\frac{5,2*1,5*10^{8 -3}}{1,3*10^{18}} = \frac{7,8*10^5}{1,3*10^{18}} = 6*10^{5 - 18} = 6*10^{-13}[/tex]
d ) = [tex]\frac{4,8*1,8*10^{18-10}}{6*1,2*10^{-8+16}} =\frac{8,64*10^8}{7,2*10^8}= 1,2*10^{8-8} = 1,2[/tex][tex]*10^0 = 1,2*1 = 1,2[/tex]
Szczegółowe wyjaśnienie:
[tex]a^m * a^n = a^{m + n}[/tex]
[tex]a^m : a^n = a^{m - n}[/tex]