Odpowiedź:
[tex]I- (3\sqrt{2})^2=9*2=18\\\II- 3\sqrt{3} *2\sqrt{3} =6*3=18\\III-\frac{6\sqrt{27} }{\sqrt{3} } =6\sqrt{9} =6*3=18\\Odp. D[/tex]
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Odpowiedź:
[tex]I- (3\sqrt{2})^2=9*2=18\\\II- 3\sqrt{3} *2\sqrt{3} =6*3=18\\III-\frac{6\sqrt{27} }{\sqrt{3} } =6\sqrt{9} =6*3=18\\Odp. D[/tex]